How to access Delayed Job instance inside Active Job - Rails 4.2 -

i'm using activejob delayed_job (4.0.6) in background , want find scheduled job deleted it.

for instance, if have

class myclass    def my_method     perform_stuff     myjob.set(wait: 1.month.from_now).perform_later(current_user)   end end 

then, if edit myclass instance , call my_method again, want cancel job , schedule new one.

as suggested in post http://www.sitepoint.com/delayed-jobs-best-practices, added 2 columns delayed job table:

table.integer :delayed_reference_id table.string  :delayed_reference_type  add_index :delayed_jobs, [:delayed_reference_id],   :name => 'delayed_jobs_delayed_reference_id' add_index :delayed_jobs, [:delayed_reference_type], :name => 'delayed_jobs_delayed_reference_type' 

so way may find delayed job , destroy it. wanted inside activejob class, maintain pattern of jobs in project.

i wanted like:

class myjob < activejob::base    after_enqueue |job|     user = self.arguments.first     job.delayed_reference_id = user.id,     job.delayed_reference_type = "user"    end    def perform(user)     delete_previous_job_if_exists(user_id)   end    def delete_previous_job_if_exists(user_id)     delayed::job.find_by(delayed_reference_id: 1, delayed_reference_type: 'user').delete   end end 

but doesn't work.

anyone had kind of issue?

two changes: 1. updated after_enqueue callback can update delayed_jobs table directly 2. fixed typo delayed_reference_id hard coded 1

this should work:

class myjob < activejob::base    after_enqueue |job|     user = self.arguments.first     delayed_job = delayed::job.find(job.provider_job_id)     delayed_job.update(delayed_reference_id:user.id,delayed_reference_type:'user')  end    def perform(user)     delete_previous_job_if_exists(user.id)   end    def delete_previous_job_if_exists(user_id)     delayed::job.find_by(delayed_reference_id: user_id, delayed_reference_type: 'user').delete   end end