c++ - confusion of char* str="ab", str and &str -

i learning pointer , code. defined pointer char (string actually) *str , pointer int *a, defined in same way. thought both str , a should address, when tried output str , &str, a , &a, found str not address, string. difference between char *str , int *a in terms of type of str , a? thank you.

#include<iostream> #include<string> using namespace std; int main() {         char *str = "fa";         cout << "str: " << str << endl;         cout << "&str: " << &str << endl;          int b = 5;         int *a = &b;         cout << "a: " << << endl;         cout << "&a: " << &a << endl; } 

this output:

str: fa &str: 0x7fff5a627280 a: 0x7fff5a62727c &a: 0x7fff5a627288 

the << operator streams has overload char * outputs c-style string. want, if it's not want, can use reinterpret_cast<void*> or addressof.