c++ - ORing of statements -

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where difference lies between these 2 style of writing. compiler showing correct answer in first case , wrong in second case.

1.

    string s[6];     for(int i=0;i<6;i++) cin>>s[i];     if(s[0]==s[2] && s[0]==s[4])  { cout<<"yes"<<endl; }     else if(s[0]==s[2] && s[0]==s[5])  { cout<<"yes"<<endl; }     else if((s[0]==s[3] && s[0]==s[5])) { cout<<"yes"<<endl; }     else if((s[0]==s[3] && s[0]==s[4])) { cout<<"yes"<<endl; }     else if((s[1]==s[2] && s[1]==s[4])) { cout<<"yes"<<endl; }     else if((s[1]==s[2] && s[1]==s[5])) { cout<<"yes"<<endl; }     else if((s[1]==s[3] && s[1]==s[4])) { cout<<"yes"<<endl; }     else if((s[1]==s[3] && s[1]==s[5])) { cout<<"yes"<<endl; }       else cout<<"no"<<endl;

and

2.

string s[6]; for(int i=0;i<6;i++) cin>>s[i]; if(s[0]==s[2]||s[0]==s[3]) {     if((s[0]==s[4]||s[0]==s[5])) { cout<<"yes"<<endl; } } else if(s[1]==s[2]||s[1]==s[3]) {     if((s[1]==s[4]||s[1]==s[5])) cout<<"yes"<<endl; }  else cout<<"no"<<endl;

consider scenario

 s[1]=s[2] , s[1]=s[4] , s[0]=s[2]//rest don't care

code1 output yes.good. consider code2

    if(s[0]==s[2]||s[0]==s[3])//s[0]==s[2] enter here    {           if((s[0]==s[4]||s[0]==s[5])) //this condition not true `yes` not printed            { cout<<"yes"<<endl; }     }    else if(s[1]==s[2]||s[1]==s[3])//now won't enter here entered if    {           if((s[1]==s[4]||s[1]==s[5])) cout<<"yes"<<endl;    }

so code2 outputs nothing.


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