Regarding Python's socket module, how do you have client always receive data -

i server , client socket connection in python,

client:

import socket import sys sys import stdin  serv = 'ip goes here' port = 8888 sock = socket.socket(socket.af_inet, socket.sock_stream) sock.connect((serv, port))   def prompt():     sys.stdout.write('<you> ')     sys.stdout.flush()   def send(x):     sock.sendall(x)     rec = 0     ex = len(x)     while rec < ex:         data = sock.recv(16)         rec += len(data)  while 1:     if sock:         data = sock.recv(16)         if len(data) == 0:             pass         print '<server> %s' % data         prompt()         msg = stdin.readline()         sock.sendall(msg) 

the way have now, if on 1 client, send "alphabet" both clients other clients not receive until send new message waiting stdin.readline() occur. wondering how make clients receive data server, , see without having have stdin.readline() happen first.

thanks

achieved wanted using threads suggested crazycasta

def receiving():     while 1:         if sock:             data = sock.recv(16)             if len(data) == 0:                 pass             print '<server> %s' % data   def sending():     while 1:         msg = stdin.readline()         sock.sendall(msg)  t1 = thread(target=receiving) t2 = thread(target=sending)  t1.start() t2.start()