python - Computing logarithm -

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i must write function computes logarithm of number x relative base b (rounded down if answer not integer). wrote function it's not working

def mylog(x, b):      result = 1     if b > x :             result -= 1         return result     elif x == b  :             return result     else :         result += 1         b *= result         return mylog(x,b)

why multiplying base result , changing base? when determine base fits input number, should dividing number base. since division means final number 1 more, add 1 result of recursive call.

def mylog(x, b):     result = 1     if b > x:             result -= 1             return result     elif x == b:             return result     else:             x /= b             return 1 + mylog(x, b)

example: mylog(32, 2):
32/2 = 16, add 1 answer
16/2 = 8, add 1 answer
...
answer = 5

some of code unnecessary though, , further edit this:

def mylog(x, b):     if b > x:             return 0     elif x == b:             return 1     else:             x /= b             return 1 + mylog(x, b)

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