prolog - Split Number in its digits, grouped in all possble ways -


i have number, let's 123, , want generate set of possible ways split it:

[[1, 23], [12, 3], [1, 2, 3]]. 

i have thought of creating powerset of [1,2,3]:

?- findall(powerset, powerset([1,2,3], powerset), z). z = [[1], [1, 2], [1, 2, 3], [2], [2, 3], [3]]. 

then combining sets , checking append/3 if concatenation initial set [1,2,3], i.e

[[1], [2, 3]] -> [1, 23] [[1, 2], [3]] -> [12, 3] [[1], [2], [3]] -> [1, 2, 3] 

do think of simpler (more elegant) solution?

i use predicate gnu prolog powerset modification

powerset(l, [h|t]):-   append([h|t], _, l). powerset([_|l], p):-   powerset(l, p). 

no need use findall/3 here---use !

int_split(x) -->    int_split__aux(x,10,[]).  int_split__aux(x,p,ds) -->    (  { x =:= 0 }    -> [ds]    ;  { x < p }    -> [[x|ds]]    ;  { x0 x mod p,         x1 x div p },       int_split__aux(x1,10,[x0|ds]),       { p1 p*10 },       int_split__aux(x,p1,ds)    ). 

sample use:

?- phrase(int_split(123),zss). zss = [[1,2,3], [12,3], [1,23], [123]].  ?- phrase(int_split(1234),zss). zss = [[1,2,3,4], [12,3,4], [1,23,4], [123,4], [1,2,34], [12,34], [1,234], [1234]]. 

Comments

Popular posts from this blog

php - Zend Framework / Skeleton-Application / Composer install issue -

c# - Better 64-bit byte array hash -

python - PyCharm Type error Message -