Python: Establishing List with List Comprehensions or Iterators -

i am trying improve coding, , algorithm performance replacing for loops list comprehensions, generators, , iterators.

i having hard time rapping head around how implement tools in itertools, , appreciate give.

i trying initialize list value 0 range of indices. here 2 ways came with:

count_list = [0 index in range(4 ** k)] 

and

total_index = list(range(4 ** k)) count_list = [0 index in total_index] 

(k represents integer of the number letter in word made of 4 letter alphabet)

when timed code in python 3.4, turned out first, using generator faster method when looking @ in isolation, when had reuse 4 ** k index loop, methods ended timing @ same speed.

what have been struggling figure out how can use iterator replicate initialization. know if wanted create list of of numbers in index use list(range()) or use

index_list = [index index, values in enumerate(words)] 

i not sure how assign value 0 each element using that.

i wondering how might use list comprehension rid of for loop. guessing need map, not sure how implement.

for index in range(4 ** k):     if frequency_array[index] >= t:         clump[index] = 1 

thank you.

to initialize list 0:

>>> my_list = [0] * 10 >>> my_list [0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 

if want use list comprehension instead of for loop, can way:

>>>t = 3 >>>l = [1,2,3,1,2,3,1,2,3,3,2,1] >>>new_list = [1 if l[i] >= t else l[i] in range(len(l))] >>>new_list [1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1] 

also, can use and - or combination, way:

>>>new_list = [l[i] >= t , 1 or l[i] in range(len(l))] >>>new_list [1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1]