python 2.7 - Problems using Scrapy to scrape craigslist.org -

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i'm using following set-up scrape prices http://puertorico.craigslist.org/search/sya

def parse(self, response):         items = selector(response).xpath("//p[@class='row']")         items in items:             item = stackitem()             item['prices'] = items.xpath("//a[@class='i']/span[@class='price']/text()").extract()             item['url'] = items.xpath("//span[@class='href']/@href").extract()               yield item

my problem when run script, of prices shown each item.. how can price of particular item url each available item?

you can try using realtive xpath expression based in context of previous one, traversing nodes until 1 want. also, use different variable in for loop, like:

import scrapy craiglist.items import stackitem  class craiglistspider(scrapy.spider):     name = "craiglist_spider"     allowed_domains = ["puertorico.craigslist.org"]     start_urls = (         'http://puertorico.craigslist.org/search/sya',     )      def parse(self, response):         items = response.selector.xpath("//p[@class='row']")         in items:             item = stackitem()             item['prices'] = i.xpath("./a/span[@class='price']/text()").extract()             item['url'] = i.xpath("./span[@class='txt']/span[@class='pl']/a/@href").extract()               yield item

it yields:

{'prices': [u'$130'], 'url': [u'/sys/5105448465.html']} 2015-07-05 23:58:22 [scrapy] debug: scraped <200 http://puertorico.craigslist.org/search/sya> {'prices': [u'$250'], 'url': [u'/sys/5096083890.html']} 2015-07-05 23:58:22 [scrapy] debug: scraped <200 http://puertorico.craigslist.org/search/sya> {'prices': [u'$100'], 'url': [u'/sys/5069848699.html']} 2015-07-05 23:58:22 [scrapy] debug: scraped <200 http://puertorico.craigslist.org/search/sya> {'prices': [u'$35'], 'url': [u'/syd/5007870110.html']} ...

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