objective c - SKShapeNode.Get Radius? -

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is possible skshapenode's radius value?

the problem is, need create identical circle after user releases it, whilst removing first circle view.

    skshapenode *reticle = [skshapenode shapenodewithcircleofradius:60];     reticle.fillcolor = [uicolor colorwithred:0 green:0 blue:0 alpha:0.3];     reticle.strokecolor = [uicolor clearcolor];     reticle.position = cgpointmake(location.x - 50, location.y + 50);     reticle.name = @"reticle";     reticle.userinteractionenabled = yes;     [self addchild:reticle];      [reticle runaction:[skaction scaleto:0.7 duration:3] completion:^{         [reticle runaction:[skaction scaleto:0.1 duration:1]];     }];

then

-(void)touchesended:(nsset *)touches withevent:(uievent *)event { ....     sknode *node = [self childnodewithname:@"reticle"];      //take position of node, draw imprint      /////////here need circle radius.      [node removefromparent];  }

how 1 take circle radius, can say

skshapenode *imprint = [skshapenode shapenodewithcircleofradius:unknownvalue];

i've tried, making exact copy of circle 

skshapenode *imprint = (skshapenode *)node;

however, still follows animation need stop, @ point at. don't want take "stopallanimations" approach.

you can use shape node's path property determine bounding box of shape cgpathgetboundingbox(path). bounds, can compute radius of circle dividing width (or height) 2. example,

cgrect boundingbox = cgpathgetboundingbox(circle.path); cgfloat radius = boundingbox.size.width / 2.0;

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