python - How to call super method? -

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i working code has 3 levels of class inheritance. lowest level derived class, syntax calling method 2 levels hierarchy, e.g. super.super call? "middle" class not implement method need call.

well, 1 way of doing it:

class grandparent(object):     def my_method(self):         print "grandparent"  class parent(grandparent):     def my_method(self):         print "parent"  class child(parent):     def my_method(self):         print "hello grandparent"         grandparent.my_method(self)

maybe not want, it's best python has unless i'm mistaken. you're asking sounds anti-pythonic , you'd have explain why you're doing give happy python way of doing things.

another example, maybe want (from comments):

class grandparent(object):     def my_method(self):         print "grandparent"  class parent(grandparent):     def some_other_method(self):         print "parent"  class child(parent):     def my_method(self):         print "hello grandparent"         super(child, self).my_method()

as can see, parent doesn't implement my_method child can still use super @ method parent "sees", i.e. grandparent's my_method.


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