deprecated - How to print the calling method name and line number for Deprecation Warning message in python? -

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my deprecate warning message in function. print out module name , line number of calling function can locate them. take open() example:

/path/to/file/group.py:180: deprecationwarning: 'u' mode deprecated  open(tmpname, 'ru') csvfile

however, own warning prints this:

/path/to/file/models.py:735: deprecationwarning: deprecated. use course_id instead!  warnings.warn("deprecated. use course_id instead!", deprecationwarning)

on line 735 of models.py warnings.warn() call located. there way make warning output parent caller's name , line number? thanks.

you can control caller want warning apply using stacklevel argument.

for instance, following code:

import warnings  def hello(s):     if isinstance(s, int):         deprecation('use of integers deprecated.')     else:         print(s)  def deprecation(msg):     warnings.warn(msg, deprecationwarning, stacklevel=3)  hello(1)

will give following warning:

warning_test.py:12: deprecationwarning: use of integers deprecated.   hello(1)

see: python documentation on warnings.warn


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