regex - How to replace a float written as a string if greater or less than? -

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i have image written in text format , need set pixel near black black , near white white.

the file use ʜꜱʟ colour space , looks this :

0,0: (19.2529%,100%,22.7451%)  #31ff3a  hsl(19.2529%,100%,22.7451%) 1,0: (18.5185%,98.1818%,21.5686%)  #2ffa37  hsl(18.5185%,98.1818%,21.5686%) 2,0: (18.4524%,90.3226%,24.3137%)  #2fe63e  hsl(18.4524%,90.3226%,24.3137%) 3,0: (18.661%,100%,22.9412%)  #30ff3b  hsl(18.661%,100%,22.9412%) 4,0: (18.9891%,100%,23.9216%)  #30ff3d  hsl(18.9891%,100%,23.9216%) 5,0: (18.9076%,100%,23.3333%)  #30ff3c  hsl(18.9076%,100%,23.3333%) 6,0: (18.7107%,86.8852%,23.9216%)  #30de3d  hsl(18.7107%,86.8852%,23.9216%) 7,0: (18.6275%,92.7273%,21.5686%)  #30ec37  hsl(18.6275%,92.7273%,21.5686%) 8,0: (19.2192%,100%,21.7647%)  #31ff38  hsl(19.2192%,100%,21.7647%) 9,0: (19.2529%,100%,22.7451%)  #31ff3a  hsl(19.2529%,100%,22.7451%) 10,0: (19.1667%,100%,23.5294%)  #31ff3c  hsl(19.1667%,100%,23.5294%) 11,0: (19.209%,96.7213%,23.9216%)  #31f73d  hsl(19.209%,96.7213%,23.9216%) 12,0: (18.7302%,84%,24.5098%)  #30d63f  hsl(18.7302%,84%,24.5098%) 13,0: (18.6275%,85%,23.5294%)  #30d93c  hsl(18.6275%,85%,23.5294%) 14,0: (18.6728%,93.1034%,22.7451%)  #30ed3a  hsl(18.6728%,93.1034%,22.7451%) 15,0: (18.7316%,100%,22.1569%)  #30ff39  hsl(18.7316%,100%,22.1569%) 16,0: (18.5841%,100%,22.1569%)  #2fff39  hsl(18.5841%,100%,22.1569%) 17,0: (18.6186%,100%,21.7647%)  #2fff38  hsl(18.6186%,100%,21.7647%) 18,0: (18.6186%,100%,21.7647%)  #2fff38  hsl(18.6186%,100%,21.7647%) 19,0: (18.5841%,100%,22.1569%)  #2fff39  hsl(18.5841%,100%,22.1569%) 20,0: (18.5345%,100%,22.7451%)  #2fff3a  hsl(18.5345%,100%,22.7451%) 21,0: (18.5345%,96.6667%,23.5294%)  #2ff73c  hsl(18.5345%,96.6667%,23.5294%) 22,0: (18.5345%,98.3051%,23.1373%)  #2ffb3b  hsl(18.5345%,98.3051%,23.1373%) 23,0: (18.5507%,100%,22.549%)  #2fff3a  hsl(18.5507%,100%,22.549%) 24,0: (18.5507%,100%,22.549%)  #2fff3a  hsl(18.5507%,100%,22.549%) 25,0: (18.5345%,98.3051%,23.1373%)  #2ffb3b  hsl(18.5345%,98.3051%,23.1373%) 26,0: (18.5345%,98.3051%,23.1373%)  #2ffb3b  hsl(18.5345%,98.3051%,23.1373%) 27,0: (18.5345%,100%,22.7451%)  #2fff3a  hsl(18.5345%,100%,22.7451%) 28,0: (18.5673%,100%,22.3529%)  #2fff39  hsl(18.5673%,100%,22.3529%) 29,0: (18.5841%,100%,22.1569%)  #2fff39  hsl(18.5841%,100%,22.1569%) 30,0: (18.5673%,100%,22.3529%)  #2fff39  hsl(18.5673%,100%,22.3529%) 31,0: (18.5507%,100%,22.549%)  #2fff3a  hsl(18.5507%,100%,22.549%) 32,0: (18.8218%,100%,22.7451%)  #30ff3a  hsl(18.8218%,100%,22.7451%) 33,0: (18.7316%,100%,22.1569%)  #30ff39  hsl(18.7316%,100%,22.1569%) 34,0: (18.7302%,84%,24.5098%)  #30d63f  hsl(18.7302%,84%,24.5098%) 35,0: (18.5824%,60%,28.4314%)  #2f9949  hsl(18.5824%,60%,28.4314%)

so how (for example) can replace values above (except first 2 numbers (x,x:) give pixel coordinate) by(0%,0%,0%) #000000 hsl(0%,0%,0%)using vim or awk or scripting tool?

i’m thinking using light/last part of ʜꜱʟ values determining if line (except[0−9],[0−9]:) need replaced, have no idea on how this.

you can try this:

awk '     begin {         black="(0%,0%,0%)  #000000  hsl(0%,0%,0%)"         white="(0%,0%,100%)  #ffffff  hsl(0%,0%,100%)"     }     {         line=$0         coords=$1         fs=","         $0=$0         match($4, "%")         sub("%.*", "", $4)         if ($4 < 25)             printf("%s %s\n", coords, black)         else if ($4 > 75)             printf("%s %s\n", coords, white)         else print line         fs=" "     } ' <img.txt

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