Reading csv file in Python and create a dictionary -

i trying read csv file in python 27 create dictionary. csv file looks like-

si1440269,si1320943,si1321085 si1440270,si1320943,si1321085,si1320739 si1440271,si1320943
si1440273,si1321058,si1320943,si1320943

number of entries in each row not fixed. first column entries should keys. code -

import csv reader = csv.reader(open('test.csv'))  result = {} column in reader:     key = column[0]     if key in result:         pass     result[key] = column[1:] print result 

output:

{'si1440273': ['si1321058', 'si1320943', 'si1320943'], '': ['', '', ''], 'si1440271': ['si1320943', '', ''], 'si1440270': ['si1320943', 'si1321085', 'si1320739'], 'si1440269': ['si1320943', 'si1321085', '']}

how can rid of null values in output? also, how can have key values in output in same order in csv file?

edit: want single row per 'key'

try this

import csv reader = csv.reader(open('test.csv'))  result = {row[0]:row[1:] row in reader if row , row[0]} print result 

if want further more eliminate null in values bellow

import csv reader = csv.reader(open('test.csv'))  result = {row[0]:[i in row[1:] if i] row in reader if row , row[0]} print result 

to preserve order of entry

from collections import ordereddict result = ordereddict() row in reader:    if row , row[0]:       result[row[0]]=[i in row[1:] if i]  # print result key in result:    print key,":" ,result[key]