rust - How does the lifetime work on constant strings? -
i read tutorial on official website , have questions on lifetime of constant strings. i error when write following code: fn get_str() -> &str { "hello world" } error: test.rs:1:17: 1:21 error: missing lifetime specifier [e0106] test.rs:1 fn get_str() -> &str { ^~~~ test.rs:1:17: 1:21 help: run `rustc --explain e0106` see detailed explanation test.rs:1:17: 1:21 help: function's return type contains borrowed value, there no value borrowed test.rs:1:17: 1:21 help: consider giving 'static lifetime error: aborting due previous error however it's ok when add parameter: fn get_str(s: &str) -> &str { "hello world" } why work? how "hello world" borrow parameter s , though has nothing 's'? lifetime elision infers full type of fn get_str(s: &str) -> &str is fn get_str<'a>(s: &'a str) -> &'a str which means return
